Anchor batch 20261005

Merkle root

0x2fe724f9fe21578e344b60fe062939096dd10e68c3c46eef159574882b4633eb

Network

Arbitrum One

Anchored

Oct 5, 2026 04:30 UTC

Contract

0xceacc40cf7b7c797d990dce7164fcccd87dad693

Written by

0x57c89Be59322a75E3B7C116d9A2e7B0332A257D1

Transaction

0xb430eba8ed008c7c02c9b9463af34a082afd7a12c6a776ee80fb5c2c17e774cf

Last re-checked against the chain

Oct 10, 2026 — the root on chain was read back and rebuilt from our rows that day

curl -s https://arb1.arbitrum.io/rpc -X POST -H 'Content-Type: application/json' \
  --data '{"jsonrpc":"2.0","id":1,"method":"eth_call","params":[{"to":"0xceacc40cf7b7c797d990dce7164fcccd87dad693","data":"0xc2b40ae4000000000000000000000000000000000000000000000000000000000135288d"},"latest"]}'

Leaves are numbered from zero in tree order. Each one is computed here by hashing that signal's stored snapshot — not copied out of a column — so a row whose bytes changed after the anchor shows up as a mismatch. Open a signal to see those bytes and the branch that carries it to the root.

Rebuild the root yourself

Take the leaves above in this order and fold them pairwise. The specification is published word for word on the verification page; the short version is below, and the rule that catches most reimplementations is the odd node — it is carried up unchanged, never paired with itself.

import hashlib

level = [bytes.fromhex(h) for h in leaves]      # in the order listed above
while len(level) > 1:
    nxt = [hashlib.sha256(level[i] + level[i + 1]).digest()
           for i in range(0, len(level) - 1, 2)]
    if len(level) % 2:
        nxt.append(level[-1])                   # promoted, never duplicated
    level = nxt

print('0x' + level[0].hex())